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2000130203113 = 739887589793
BaseRepresentation
bin11101000110110001000…
…011001101110111101001
321002012200111211212001121
4131012301003031313221
5230232231312444423
64130502551415241
7264335043133000
oct35066103156751
97065614755047
102000130203113
117012833a1369
1228377b684521
131167c4521433
146cb41ca3c37
153706464b45d
hex1d1b10cdde9

2000130203113 has 16 divisors (see below), whose sum is σ = 2332753228800. Its totient is φ = 1714221011328.

The previous prime is 2000130203111. The next prime is 2000130203117. The reversal of 2000130203113 is 3113020310002.

It is not a de Polignac number, because 2000130203113 - 21 = 2000130203111 is a prime.

It is a super-3 number, since 3×20001302031133 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2000130203111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3096345 + ... + 3686137.

It is an arithmetic number, because the mean of its divisors is an integer number (145797076800).

Almost surely, 22000130203113 is an apocalyptic number.

It is an amenable number.

2000130203113 is a deficient number, since it is larger than the sum of its proper divisors (332623025687).

2000130203113 is an frugal number, since it uses more digits than its factorization.

2000130203113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 599701 (or 599687 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 2000130203113 its reverse (3113020310002), we get a palindrome (5113150513115).

The spelling of 2000130203113 in words is "two trillion, one hundred thirty million, two hundred three thousand, one hundred thirteen".

Divisors: 1 7 49 343 9887 69209 484463 589793 3391241 4128551 28899857 202298999 5831283391 40818983737 285732886159 2000130203113