200013131101011 has 4 divisors (see below), whose sum is σ = 266684174801352. Its totient is φ = 133342087400672.

The previous prime is 200013131100997. The next prime is 200013131101019. The reversal of 200013131101011 is 110101131310002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200013131101011 - 2²¹ = 200013129003859 is a prime.

It is a super-2 number, since 2×200013131101011² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (200013131101019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33335521850166 + ... + 33335521850171.

It is an arithmetic number, because the mean of its divisors is an integer number (66671043700338).

Almost surely, 2^{200013131101011} is an apocalyptic number.

200013131101011 is a deficient number, since it is larger than the sum of its proper divisors (66671043700341).

200013131101011 is an equidigital number, since it uses as much as digits as its factorization.

200013131101011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66671043700340.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 200013131101011 its reverse (110101131310002), we get a palindrome (310114262411013).

The spelling of 200013131101011 in words is "two hundred trillion, thirteen billion, one hundred thirty-one million, one hundred one thousand, eleven".