20001321112433 has 4 divisors (see below), whose sum is σ = 20001585172800. Its totient is φ = 20001057052068.

The previous prime is 20001321112373. The next prime is 20001321112463. The reversal of 20001321112433 is 33421112310002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20001321112433 - 2¹⁴ = 20001321096049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20001321112399 and 20001321112408.

It is not an unprimeable number, because it can be changed into a prime (20001321112463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131916533 + ... + 132068066.

It is an arithmetic number, because the mean of its divisors is an integer number (5000396293200).

Almost surely, 2^{20001321112433} is an apocalyptic number.

It is an amenable number.

20001321112433 is a deficient number, since it is larger than the sum of its proper divisors (264060367).

20001321112433 is an equidigital number, since it uses as much as digits as its factorization.

20001321112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 264060366.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 20001321112433 its reverse (33421112310002), we get a palindrome (53422433422435).

The spelling of 20001321112433 in words is "twenty trillion, one billion, three hundred twenty-one million, one hundred twelve thousand, four hundred thirty-three".