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200013622651 = 1071869286193
BaseRepresentation
bin1011101001000110111…
…1011010110101111011
3201010021021220210021001
42322101233122311323
511234111441411101
6231515054025431
720310344512123
oct2722157326573
9633237823231
10200013622651
1177909526097
12329201a8277
1315b270ab90b
149975c29c83
155309765901
hex2e91bdad7b

200013622651 has 4 divisors (see below), whose sum is σ = 201882908952. Its totient is φ = 198144336352.

The previous prime is 200013622643. The next prime is 200013622727. The reversal of 200013622651 is 156226310002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200013622651 - 23 = 200013622643 is a prime.

It is a super-3 number, since 3×2000136226513 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200013622631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 934642990 + ... + 934643203.

It is an arithmetic number, because the mean of its divisors is an integer number (50470727238).

Almost surely, 2200013622651 is an apocalyptic number.

200013622651 is a deficient number, since it is larger than the sum of its proper divisors (1869286301).

200013622651 is a wasteful number, since it uses less digits than its factorization.

200013622651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1869286300.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 200013622651 its reverse (156226310002), we get a palindrome (356239932653).

The spelling of 200013622651 in words is "two hundred billion, thirteen million, six hundred twenty-two thousand, six hundred fifty-one".

Divisors: 1 107 1869286193 200013622651