Base | Representation |
---|---|
bin | 101101011110101011001100… |
… | …010101110110010000010011 |
3 | 222020012201201120010112002220 |
4 | 231132223030111312100103 |
5 | 202204112033121112120 |
6 | 1545223540031112123 |
7 | 60062654301211062 |
oct | 5536531425662023 |
9 | 866181646115086 |
10 | 200020055254035 |
11 | 58807035751565 |
12 | 1a525287972643 |
13 | 877ba6c2414c3 |
14 | 37570453b01d9 |
15 | 181cea9ac1b40 |
hex | b5eacc576413 |
200020055254035 has 16 divisors (see below), whose sum is σ = 322179954775200. Its totient is φ = 105961407345920.
The previous prime is 200020055254013. The next prime is 200020055254039. The reversal of 200020055254035 is 530452550020002.
It is not a de Polignac number, because 200020055254035 - 29 = 200020055253523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200020055253987 and 200020055254005.
It is not an unprimeable number, because it can be changed into a prime (200020055254039) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44747213706 + ... + 44747218175.
It is an arithmetic number, because the mean of its divisors is an integer number (20136247173450).
Almost surely, 2200020055254035 is an apocalyptic number.
200020055254035 is a deficient number, since it is larger than the sum of its proper divisors (122159899521165).
200020055254035 is a wasteful number, since it uses less digits than its factorization.
200020055254035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89494432038.
The product of its (nonzero) digits is 60000, while the sum is 33.
The spelling of 200020055254035 in words is "two hundred trillion, twenty billion, fifty-five million, two hundred fifty-four thousand, thirty-five".
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