200024113 has 4 divisors (see below), whose sum is σ = 201348928. Its totient is φ = 198699300.

The previous prime is 200024093. The next prime is 200024131. The reversal of 200024113 is 311420002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200024113 - 2⁵ = 200024081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200024093 and 200024102.

It is not an unprimeable number, because it can be changed into a prime (200022113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 662181 + ... + 662482.

It is an arithmetic number, because the mean of its divisors is an integer number (50337232).

Almost surely, 2^200024113 is an apocalyptic number.

It is an amenable number.

200024113 is a deficient number, since it is larger than the sum of its proper divisors (1324815).

200024113 is a wasteful number, since it uses less digits than its factorization.

200024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1324814.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 200024113 is about 14142.9881213271. The cubic root of 200024113 is about 584.8270489780.

Adding to 200024113 its reverse (311420002), we get a palindrome (511444115).

The spelling of 200024113 in words is "two hundred million, twenty-four thousand, one hundred thirteen".