Base | Representation |
---|---|
bin | 101101011110111000001011… |
… | …110000001000110101110011 |
3 | 222020021001201200011212101012 |
4 | 231132320023300020311303 |
5 | 202204324120011344103 |
6 | 1545234204113301135 |
7 | 60063660044541101 |
oct | 5536701360106563 |
9 | 866231650155335 |
10 | 200034004012403 |
11 | 58811a43431140 |
12 | 1a527b1b2647ab |
13 | 878018304ba92 |
14 | 37579a9b48c71 |
15 | 181d5244822d8 |
hex | b5ee0bc08d73 |
200034004012403 has 16 divisors (see below), whose sum is σ = 232611766540800. Its totient is φ = 170097354254880.
The previous prime is 200034004012397. The next prime is 200034004012421. The reversal of 200034004012403 is 304210400430002.
It is a cyclic number.
It is not a de Polignac number, because 200034004012403 - 232 = 200029709045107 is a prime.
It is a super-2 number, since 2×2000340040124032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200034004012433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6057581576 + ... + 6057614597.
It is an arithmetic number, because the mean of its divisors is an integer number (14538235408800).
Almost surely, 2200034004012403 is an apocalyptic number.
200034004012403 is a deficient number, since it is larger than the sum of its proper divisors (32577762528397).
200034004012403 is a wasteful number, since it uses less digits than its factorization.
200034004012403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12115196282.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 200034004012403 its reverse (304210400430002), we get a palindrome (504244404442405).
The spelling of 200034004012403 in words is "two hundred trillion, thirty-four billion, four million, twelve thousand, four hundred three".
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