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20004010313 = 717168100927
BaseRepresentation
bin10010101000010101…
…001111100101001001
31220122010002000100212
4102220111033211021
5311432011312223
613104551210505
71305501165530
oct225025174511
956563060325
1020004010313
118535819031
123a63376a35
131b6a4800c1
14d7aa4b317
157c12ae278
hex4a854f949

20004010313 has 8 divisors (see below), whose sum is σ = 24206533632. Its totient is φ = 16137688896.

The previous prime is 20004010291. The next prime is 20004010337. The reversal of 20004010313 is 31301040002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20004010313 - 222 = 19999816009 is a prime.

It is a super-3 number, since 3×200040103133 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20004010613) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84050345 + ... + 84050582.

It is an arithmetic number, because the mean of its divisors is an integer number (3025816704).

Almost surely, 220004010313 is an apocalyptic number.

It is an amenable number.

20004010313 is a deficient number, since it is larger than the sum of its proper divisors (4202523319).

20004010313 is a wasteful number, since it uses less digits than its factorization.

20004010313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168100951.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 20004010313 its reverse (31301040002), we get a palindrome (51305050315).

The spelling of 20004010313 in words is "twenty billion, four million, ten thousand, three hundred thirteen".

Divisors: 1 7 17 119 168100927 1176706489 2857715759 20004010313