Base | Representation |
---|---|
bin | 111011100111101… |
… | …0110000001000001 |
3 | 12011102022111020112 |
4 | 1313033112001001 |
5 | 13044112323131 |
6 | 530301521105 |
7 | 100401030464 |
oct | 16717260101 |
9 | 5142274215 |
10 | 2000511041 |
11 | 937266611 |
12 | 479b73195 |
13 | 25b5c5b59 |
14 | 14d98d2db |
15 | ba96402b |
hex | 773d6041 |
2000511041 has 4 divisors (see below), whose sum is σ = 2000602500. Its totient is φ = 2000419584.
The previous prime is 2000511001. The next prime is 2000511047. The reversal of 2000511041 is 1401150002.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 840768016 + 1159743025 = 28996^2 + 34055^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2000511041 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (2000511047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8585 + ... + 63833.
It is an arithmetic number, because the mean of its divisors is an integer number (500150625).
Almost surely, 22000511041 is an apocalyptic number.
It is an amenable number.
2000511041 is a deficient number, since it is larger than the sum of its proper divisors (91459).
2000511041 is an equidigital number, since it uses as much as digits as its factorization.
2000511041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91458.
The product of its (nonzero) digits is 40, while the sum is 14.
The square root of 2000511041 is about 44727.0727971326. The cubic root of 2000511041 is about 1260.0283526416.
Adding to 2000511041 its reverse (1401150002), we get a palindrome (3401661043).
The spelling of 2000511041 in words is "two billion, five hundred eleven thousand, forty-one".
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