Base | Representation |
---|---|
bin | 1011101001011011100… |
… | …1011000011000110001 |
3 | 201010111022200022110202 |
4 | 2322112321120120301 |
5 | 11234301112320423 |
6 | 231531424004545 |
7 | 20312444646245 |
oct | 2722671303061 |
9 | 633438608422 |
10 | 200100120113 |
11 | 779533349a3 |
12 | 32945160755 |
13 | 15b3bca554a |
14 | 9983504425 |
15 | 531214e728 |
hex | 2e96e58631 |
200100120113 has 4 divisors (see below), whose sum is σ = 200446914660. Its totient is φ = 199753325568.
The previous prime is 200100120109. The next prime is 200100120131. The reversal of 200100120113 is 311021001002.
200100120113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 115893946624 + 84206173489 = 340432^2 + 290183^2 .
It is a cyclic number.
It is not a de Polignac number, because 200100120113 - 22 = 200100120109 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200100120094 and 200100120103.
It is not an unprimeable number, because it can be changed into a prime (200100120713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173396408 + ... + 173397561.
It is an arithmetic number, because the mean of its divisors is an integer number (50111728665).
Almost surely, 2200100120113 is an apocalyptic number.
It is an amenable number.
200100120113 is a deficient number, since it is larger than the sum of its proper divisors (346794547).
200100120113 is an equidigital number, since it uses as much as digits as its factorization.
200100120113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 346794546.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 200100120113 its reverse (311021001002), we get a palindrome (511121121115).
The spelling of 200100120113 in words is "two hundred billion, one hundred million, one hundred twenty thousand, one hundred thirteen".
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