Base | Representation |
---|---|
bin | 1011101001011011110… |
… | …0110000001101111011 |
3 | 201010111101100020011001 |
4 | 2322112330300031323 |
5 | 11234301324113110 |
6 | 231531454545431 |
7 | 20312455320523 |
oct | 2722674601573 |
9 | 633441306131 |
10 | 200101004155 |
11 | 77953889108 |
12 | 32945508277 |
13 | 15b3c224a50 |
14 | 9983694683 |
15 | 531227663a |
hex | 2e96f3037b |
200101004155 has 16 divisors (see below), whose sum is σ = 258615010080. Its totient is φ = 147753785088.
The previous prime is 200101004149. The next prime is 200101004171. The reversal of 200101004155 is 551400101002.
It is not a de Polignac number, because 200101004155 - 25 = 200101004123 is a prime.
It is a super-3 number, since 3×2001010041553 (a number of 35 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 634959 + ... + 896311.
It is an arithmetic number, because the mean of its divisors is an integer number (16163438130).
Almost surely, 2200101004155 is an apocalyptic number.
200101004155 is a deficient number, since it is larger than the sum of its proper divisors (58514005925).
200101004155 is a wasteful number, since it uses less digits than its factorization.
200101004155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 273150.
The product of its (nonzero) digits is 200, while the sum is 19.
Adding to 200101004155 its reverse (551400101002), we get a palindrome (751501105157).
The spelling of 200101004155 in words is "two hundred billion, one hundred one million, four thousand, one hundred fifty-five".
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