Base | Representation |
---|---|
bin | 1001000110010111111001… |
… | …11011111011001010001011 |
3 | 2121211221211022212210012120 |
4 | 10203023330323323022023 |
5 | 10110321343003411021 |
6 | 110320320505542323 |
7 | 4133455304042034 |
oct | 443137473731213 |
9 | 77757738783176 |
10 | 20010201232011 |
11 | 6415307a266a1 |
12 | 22b213baa49a3 |
13 | b21c5289a1b3 |
14 | 4d26db003a8b |
15 | 24a7a07432c6 |
hex | 1232fcefb28b |
20010201232011 has 8 divisors (see below), whose sum is σ = 26687714672640. Its totient is φ = 13336410973032.
The previous prime is 20010201231953. The next prime is 20010201232061. The reversal of 20010201232011 is 11023210201002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20010201232011 - 219 = 20010200707723 is a prime.
It is a super-2 number, since 2×200102012320112 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (20010201232061) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 930782871 + ... + 930804368.
It is an arithmetic number, because the mean of its divisors is an integer number (3335964334080).
Almost surely, 220010201232011 is an apocalyptic number.
20010201232011 is a deficient number, since it is larger than the sum of its proper divisors (6677513440629).
20010201232011 is a wasteful number, since it uses less digits than its factorization.
20010201232011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1861590825.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 20010201232011 its reverse (11023210201002), we get a palindrome (31033411433013).
The spelling of 20010201232011 in words is "twenty trillion, ten billion, two hundred one million, two hundred thirty-two thousand, eleven".
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