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20011011003 = 322239993053
BaseRepresentation
bin10010101000101111…
…111100101110111011
31220122121020200111200
4102220233330232323
5311440304323003
613105401225243
71305614533644
oct225057745673
956577220450
1020011011003
11853976a825
123a65792223
131b6ba61719
14d7b9506cb
157c1be36a3
hex4a8bfcbbb

20011011003 has 12 divisors (see below), whose sum is σ = 28917732480. Its totient is φ = 13334702256.

The previous prime is 20011011001. The next prime is 20011011073. The reversal of 20011011003 is 30011011002.

It is not a de Polignac number, because 20011011003 - 21 = 20011011001 is a prime.

It is a super-2 number, since 2×200110110032 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is not an unprimeable number, because it can be changed into a prime (20011011001) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 476376 + ... + 516677.

It is an arithmetic number, because the mean of its divisors is an integer number (2409811040).

Almost surely, 220011011003 is an apocalyptic number.

20011011003 is a deficient number, since it is larger than the sum of its proper divisors (8906721477).

20011011003 is a wasteful number, since it uses less digits than its factorization.

20011011003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 995298 (or 995295 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

Adding to 20011011003 its reverse (30011011002), we get a palindrome (50022022005).

Subtracting 20011011003 from its reverse (30011011002), we obtain a palindrome (9999999999).

The spelling of 20011011003 in words is "twenty billion, eleven million, eleven thousand, three".

Divisors: 1 3 9 2239 6717 20151 993053 2979159 8937477 2223445667 6670337001 20011011003