Base | Representation |
---|---|
bin | 1011101001011101111… |
… | …1111000000000110001 |
3 | 201010112000122222201210 |
4 | 2322113133320000301 |
5 | 11234311203223441 |
6 | 231532424150333 |
7 | 20312626505142 |
oct | 2722737700061 |
9 | 633460588653 |
10 | 200110211121 |
11 | 77958aa7477 |
12 | 329486083a9 |
13 | 15b410c9662 |
14 | 99849adac9 |
15 | 5312e94616 |
hex | 2e977f8031 |
200110211121 has 4 divisors (see below), whose sum is σ = 266813614832. Its totient is φ = 133406807412.
The previous prime is 200110211107. The next prime is 200110211159. The reversal of 200110211121 is 121112011002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 200110211121 - 29 = 200110210609 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200110211097 and 200110211106.
It is not an unprimeable number, because it can be changed into a prime (200110211921) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33351701851 + ... + 33351701856.
It is an arithmetic number, because the mean of its divisors is an integer number (66703403708).
Almost surely, 2200110211121 is an apocalyptic number.
It is an amenable number.
200110211121 is a deficient number, since it is larger than the sum of its proper divisors (66703403711).
200110211121 is an equidigital number, since it uses as much as digits as its factorization.
200110211121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66703403710.
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 200110211121 its reverse (121112011002), we get a palindrome (321222222123).
The spelling of 200110211121 in words is "two hundred billion, one hundred ten million, two hundred eleven thousand, one hundred twenty-one".
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