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20011101103003 = 46143408028423
BaseRepresentation
bin1001000110011001100101…
…00100101010001110011011
32121212001011001010222010211
410203030302210222032123
510110330213340244003
6110320550053151551
74133516511602443
oct443146244521633
977761131128124
1020011101103003
11641572998002a
1222b235132b5b7
13b22067149c3a
144d2784729123
1524a80474696d
hex12333292a39b

20011101103003 has 4 divisors (see below), whose sum is σ = 20054509131888. Its totient is φ = 19967693074120.

The previous prime is 20011101102959. The next prime is 20011101103027. The reversal of 20011101103003 is 30030110111002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20011101103003 - 29 = 20011101102491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20011101103093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21704013751 + ... + 21704014672.

It is an arithmetic number, because the mean of its divisors is an integer number (5013627282972).

Almost surely, 220011101103003 is an apocalyptic number.

20011101103003 is a deficient number, since it is larger than the sum of its proper divisors (43408028885).

20011101103003 is an equidigital number, since it uses as much as digits as its factorization.

20011101103003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43408028884.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 20011101103003 its reverse (30030110111002), we get a palindrome (50041211214005).

The spelling of 20011101103003 in words is "twenty trillion, eleven billion, one hundred one million, one hundred three thousand, three".

Divisors: 1 461 43408028423 20011101103003