Base | Representation |
---|---|
bin | 1001000110011001100110… |
… | …01110111111101111110001 |
3 | 2121212001011211000211000012 |
4 | 10203030303032333233301 |
5 | 10110330224210414301 |
6 | 110320551131104305 |
7 | 4133520005124632 |
oct | 443146316775761 |
9 | 77761154024005 |
10 | 20011112201201 |
11 | 64157351702a0 |
12 | 22b2354ba2095 |
13 | b22069534614 |
14 | 4d2785db7889 |
15 | 24a8056d9ebb |
hex | 1233333bfbf1 |
20011112201201 has 16 divisors (see below), whose sum is σ = 21844627274880. Its totient is φ = 18179988266880.
The previous prime is 20011112201153. The next prime is 20011112201203. The reversal of 20011112201201 is 10210221111002.
It is not a de Polignac number, because 20011112201201 - 230 = 20010038459377 is a prime.
It is a super-3 number, since 3×200111122012013 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20011112201203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 104124740 + ... + 104316746.
It is an arithmetic number, because the mean of its divisors is an integer number (1365289204680).
Almost surely, 220011112201201 is an apocalyptic number.
It is an amenable number.
20011112201201 is a deficient number, since it is larger than the sum of its proper divisors (1833515073679).
20011112201201 is a wasteful number, since it uses less digits than its factorization.
20011112201201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 198184.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 20011112201201 its reverse (10210221111002), we get a palindrome (30221333312203).
The spelling of 20011112201201 in words is "twenty trillion, eleven billion, one hundred twelve million, two hundred one thousand, two hundred one".
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