200111201403 has 4 divisors (see below), whose sum is σ = 266814935208. Its totient is φ = 133407467600.

The previous prime is 200111201401. The next prime is 200111201417. The reversal of 200111201403 is 304102111002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200111201403 - 2¹ = 200111201401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (200111201401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33351866898 + ... + 33351866903.

It is an arithmetic number, because the mean of its divisors is an integer number (66703733802).

Almost surely, 2^200111201403 is an apocalyptic number.

200111201403 is a deficient number, since it is larger than the sum of its proper divisors (66703733805).

200111201403 is an equidigital number, since it uses as much as digits as its factorization.

200111201403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66703733804.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 200111201403 its reverse (304102111002), we get a palindrome (504213312405).

The spelling of 200111201403 in words is "two hundred billion, one hundred eleven million, two hundred one thousand, four hundred three".