Base | Representation |
---|---|
bin | 10111110110101… |
… | …11011111110001 |
3 | 111221112202012202 |
4 | 23323113133301 |
5 | 402212041423 |
6 | 31505032545 |
7 | 4646632145 |
oct | 1373273761 |
9 | 457482182 |
10 | 200112113 |
11 | a2a5a213 |
12 | 57025755 |
13 | 325c6346 |
14 | 1c811225 |
15 | 1287c728 |
hex | bed77f1 |
200112113 has 4 divisors (see below), whose sum is σ = 200482548. Its totient is φ = 199741680.
The previous prime is 200112109. The next prime is 200112127. The reversal of 200112113 is 311211002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 152942689 + 47169424 = 12367^2 + 6868^2 .
It is a cyclic number.
It is not a de Polignac number, because 200112113 - 22 = 200112109 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200112094 and 200112103.
It is not an unprimeable number, because it can be changed into a prime (200112163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184406 + ... + 185487.
It is an arithmetic number, because the mean of its divisors is an integer number (50120637).
Almost surely, 2200112113 is an apocalyptic number.
It is an amenable number.
200112113 is a deficient number, since it is larger than the sum of its proper divisors (370435).
200112113 is an equidigital number, since it uses as much as digits as its factorization.
200112113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 370434.
The product of its (nonzero) digits is 12, while the sum is 11.
The square root of 200112113 is about 14146.0988615236. The cubic root of 200112113 is about 584.9128006975.
Adding to 200112113 its reverse (311211002), we get a palindrome (511323115).
The spelling of 200112113 in words is "two hundred million, one hundred twelve thousand, one hundred thirteen".
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