Base | Representation |
---|---|
bin | 101101100000000001000000… |
… | …101110101011000100110001 |
3 | 222020112112120102221000110211 |
4 | 231200001000232223010301 |
5 | 202212114242232411423 |
6 | 1545334135424424121 |
7 | 60102425630461663 |
oct | 5540010056530461 |
9 | 866475512830424 |
10 | 200112202232113 |
11 | 58842121277aa6 |
12 | 1a53b103778041 |
13 | 8787665abc3c2 |
14 | 375b6a74a6533 |
15 | 182059e69510d |
hex | b60040bab131 |
200112202232113 has 4 divisors (see below), whose sum is σ = 208812732763968. Its totient is φ = 191411671700260.
The previous prime is 200112202231939. The next prime is 200112202232219. The reversal of 200112202232113 is 311232202211002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 200112202232113 - 233 = 200103612297521 is a prime.
It is a super-2 number, since 2×2001122022321132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200112202230113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4350265265893 + ... + 4350265265938.
It is an arithmetic number, because the mean of its divisors is an integer number (52203183190992).
Almost surely, 2200112202232113 is an apocalyptic number.
200112202232113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
200112202232113 is a deficient number, since it is larger than the sum of its proper divisors (8700530531855).
200112202232113 is an equidigital number, since it uses as much as digits as its factorization.
200112202232113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8700530531854.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 200112202232113 its reverse (311232202211002), we get a palindrome (511344404443115).
The spelling of 200112202232113 in words is "two hundred trillion, one hundred twelve billion, two hundred two million, two hundred thirty-two thousand, one hundred thirteen".
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