Base | Representation |
---|---|
bin | 1001000110011001111110… |
… | …10101111100000100100001 |
3 | 2121212001200222021201200021 |
4 | 10203030333111330010201 |
5 | 10110331133212111440 |
6 | 110321023225153441 |
7 | 4133525022625621 |
oct | 443147725740441 |
9 | 77761628251607 |
10 | 20011315347745 |
11 | 64158299022a7 |
12 | 22b23b102b881 |
13 | b2209c650b87 |
14 | 4d27a4d78881 |
15 | 24a81846684a |
hex | 12333f57c121 |
20011315347745 has 4 divisors (see below), whose sum is σ = 24013578417300. Its totient is φ = 16009052278192.
The previous prime is 20011315347733. The next prime is 20011315347791. The reversal of 20011315347745 is 54774351311002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12942092590144 + 7069222757601 = 3597512^2 + 2658801^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20011315347745 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001131534770 + ... + 2001131534779.
It is an arithmetic number, because the mean of its divisors is an integer number (6003394604325).
Almost surely, 220011315347745 is an apocalyptic number.
It is an amenable number.
20011315347745 is a deficient number, since it is larger than the sum of its proper divisors (4002263069555).
20011315347745 is an equidigital number, since it uses as much as digits as its factorization.
20011315347745 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4002263069554.
The product of its (nonzero) digits is 352800, while the sum is 43.
Adding to 20011315347745 its reverse (54774351311002), we get a palindrome (74785666658747).
The spelling of 20011315347745 in words is "twenty trillion, eleven billion, three hundred fifteen million, three hundred forty-seven thousand, seven hundred forty-five".
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