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200114222411003 = 1238377116159393
BaseRepresentation
bin101101100000000010111001…
…001001000010110011111011
3222020112201210020020201221012
4231200002321021002303323
5202212132411414123003
61545335112112104135
760102526660636235
oct5540027111026373
9866481706221835
10200114222411003
1158842a6864732a
121a53b58823504b
1387878c84b0424
14375b8198d5255
15182066bbe18d8
hexb600b9242cfb

200114222411003 has 4 divisors (see below), whose sum is σ = 200114250954168. Its totient is φ = 200114193867840.

The previous prime is 200114222410967. The next prime is 200114222411017. The reversal of 200114222411003 is 300114222411002.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 200114222411003 - 230 = 200113148669179 is a prime.

It is a super-2 number, since 2×2001142224110032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200114222411003.

It is not an unprimeable number, because it can be changed into a prime (200114222411083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4304075 + ... + 20463467.

It is an arithmetic number, because the mean of its divisors is an integer number (50028562738542).

Almost surely, 2200114222411003 is an apocalyptic number.

200114222411003 is a deficient number, since it is larger than the sum of its proper divisors (28543165).

200114222411003 is a wasteful number, since it uses less digits than its factorization.

200114222411003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28543164.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 200114222411003 its reverse (300114222411002), we get a palindrome (500228444822005).

Subtracting 200114222411003 from its reverse (300114222411002), we obtain a palindrome (99999999999999).

The spelling of 200114222411003 in words is "two hundred trillion, one hundred fourteen billion, two hundred twenty-two million, four hundred eleven thousand, three".

Divisors: 1 12383771 16159393 200114222411003