Base | Representation |
---|---|
bin | 1011101001100000011… |
… | …0011010010010110011 |
3 | 201010112201200012220212 |
4 | 2322120012122102303 |
5 | 11234321300004021 |
6 | 231533424454335 |
7 | 20313111410543 |
oct | 2723006322263 |
9 | 633481605825 |
10 | 200120313011 |
11 | 77963777143 |
12 | 3294ba7a3ab |
13 | 15b432256c8 |
14 | 998607d323 |
15 | 5313cdc85b |
hex | 2e9819a4b3 |
200120313011 has 4 divisors (see below), whose sum is σ = 200693724000. Its totient is φ = 199546902024.
The previous prime is 200120312929. The next prime is 200120313013. The reversal of 200120313011 is 110313021002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200120313011 - 234 = 182940443827 is a prime.
It is a super-3 number, since 3×2001203130113 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200120313013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286704971 + ... + 286705668.
It is an arithmetic number, because the mean of its divisors is an integer number (50173431000).
Almost surely, 2200120313011 is an apocalyptic number.
200120313011 is a deficient number, since it is larger than the sum of its proper divisors (573410989).
200120313011 is an equidigital number, since it uses as much as digits as its factorization.
200120313011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 573410988.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 200120313011 its reverse (110313021002), we get a palindrome (310433334013).
The spelling of 200120313011 in words is "two hundred billion, one hundred twenty million, three hundred thirteen thousand, eleven".
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