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200120313201 = 366706771067
BaseRepresentation
bin1011101001100000011…
…0011010010101110001
3201010112201200020011220
42322120012122111301
511234321300010301
6231533424455253
720313111411234
oct2723006322561
9633481606156
10200120313201
11779637772a6
123294ba7a529
1315b43225813
14998607d41b
155313cdc936
hex2e9819a571

200120313201 has 4 divisors (see below), whose sum is σ = 266827084272. Its totient is φ = 133413542132.

The previous prime is 200120313191. The next prime is 200120313203. The reversal of 200120313201 is 102313021002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200120313201 - 27 = 200120313073 is a prime.

It is a super-3 number, since 3×2001203132013 (a number of 35 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (200120313203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33353385531 + ... + 33353385536.

It is an arithmetic number, because the mean of its divisors is an integer number (66706771068).

Almost surely, 2200120313201 is an apocalyptic number.

It is an amenable number.

200120313201 is a deficient number, since it is larger than the sum of its proper divisors (66706771071).

200120313201 is an equidigital number, since it uses as much as digits as its factorization.

200120313201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66706771070.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 200120313201 its reverse (102313021002), we get a palindrome (302433334203).

The spelling of 200120313201 in words is "two hundred billion, one hundred twenty million, three hundred thirteen thousand, two hundred one".

Divisors: 1 3 66706771067 200120313201