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20012122113 = 36670707371
BaseRepresentation
bin10010101000110100…
…001100000000000001
31220122200100010122220
4102220310030000001
5311441100401423
613105441121253
71305630142224
oct225064140001
956580303586
1020012122113
11853a3595a5
123a66029229
131b6c060399
14d7bb5d5bb
157c1d629e3
hex4a8d0c001

20012122113 has 4 divisors (see below), whose sum is σ = 26682829488. Its totient is φ = 13341414740.

The previous prime is 20012122111. The next prime is 20012122129. The reversal of 20012122113 is 31122121002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20012122113 - 21 = 20012122111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20012122092 and 20012122101.

It is not an unprimeable number, because it can be changed into a prime (20012122111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3335353683 + ... + 3335353688.

It is an arithmetic number, because the mean of its divisors is an integer number (6670707372).

Almost surely, 220012122113 is an apocalyptic number.

It is an amenable number.

20012122113 is a deficient number, since it is larger than the sum of its proper divisors (6670707375).

20012122113 is an equidigital number, since it uses as much as digits as its factorization.

20012122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6670707374.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20012122113 its reverse (31122121002), we get a palindrome (51134243115).

The spelling of 20012122113 in words is "twenty billion, twelve million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 6670707371 20012122113