200122121030113 has 4 divisors (see below), whose sum is σ = 200126124082948. Its totient is φ = 200118117977280.

The previous prime is 200122121030099. The next prime is 200122121030129. The reversal of 200122121030113 is 311030121221002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 98323545767329 + 101798575262784 = 9915823^2 + 10089528^2 .

It is a cyclic number.

It is not a de Polignac number, because 200122121030113 - 2⁵ = 200122121030081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200122121031113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001451428 + ... + 2001551413.

It is an arithmetic number, because the mean of its divisors is an integer number (50031531020737).

Almost surely, 2^{200122121030113} is an apocalyptic number.

It is an amenable number.

200122121030113 is a deficient number, since it is larger than the sum of its proper divisors (4003052835).

200122121030113 is an equidigital number, since it uses as much as digits as its factorization.

200122121030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4003052834.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 200122121030113 its reverse (311030121221002), we get a palindrome (511152242251115).

The spelling of 200122121030113 in words is "two hundred trillion, one hundred twenty-two billion, one hundred twenty-one million, thirty thousand, one hundred thirteen".