Base | Representation |
---|---|
bin | 1001000110011101010110… |
… | …01010000000000001110011 |
3 | 2121212020101000212210021012 |
4 | 10203032223022000001303 |
5 | 10110343334241020210 |
6 | 110321522522221135 |
7 | 4133620605354614 |
oct | 443165312000163 |
9 | 77766330783235 |
10 | 20013124157555 |
11 | 6416577933941 |
12 | 22b28169547ab |
13 | b222ca306b39 |
14 | 4d28d72a5c0b |
15 | 24a8c2160305 |
hex | 1233ab280073 |
20013124157555 has 8 divisors (see below), whose sum is σ = 24016338389232. Its totient is φ = 16010106392608.
The previous prime is 20013124157513. The next prime is 20013124157557. The reversal of 20013124157555 is 55575142131002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20013124157555 - 228 = 20012855722099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20013124157557) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48892484 + ... + 49300113.
It is an arithmetic number, because the mean of its divisors is an integer number (3002042298654).
Almost surely, 220013124157555 is an apocalyptic number.
20013124157555 is a deficient number, since it is larger than the sum of its proper divisors (4003214231677).
20013124157555 is an equidigital number, since it uses as much as digits as its factorization.
20013124157555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98233365.
The product of its (nonzero) digits is 210000, while the sum is 41.
Adding to 20013124157555 its reverse (55575142131002), we get a palindrome (75588266288557).
The spelling of 20013124157555 in words is "twenty trillion, thirteen billion, one hundred twenty-four million, one hundred fifty-seven thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •