Base | Representation |
---|---|
bin | 1001000110011101010111… |
… | …10000010111011001100001 |
3 | 2121212020101201210202011000 |
4 | 10203032223300113121201 |
5 | 10110343344324333003 |
6 | 110321523521542213 |
7 | 4133621060013111 |
oct | 443165360273141 |
9 | 77766351722130 |
10 | 20013134214753 |
11 | 6416582582a79 |
12 | 22b281a1a4969 |
13 | b222cc418744 |
14 | 4d28d8763041 |
15 | 24a8c2e9a1a3 |
hex | 1233abc17661 |
20013134214753 has 16 divisors (see below), whose sum is σ = 29649368390400. Its totient is φ = 13341963177360.
The previous prime is 20013134214691. The next prime is 20013134214833. The reversal of 20013134214753 is 35741243131002.
20013134214753 is a `hidden beast` number, since 2 + 0 + 0 + 131 + 34 + 21 + 475 + 3 = 666.
It is not a de Polignac number, because 20013134214753 - 228 = 20012865779297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20013134214653) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 558138 + ... + 6351203.
It is an arithmetic number, because the mean of its divisors is an integer number (1853085524400).
Almost surely, 220013134214753 is an apocalyptic number.
It is an amenable number.
20013134214753 is a deficient number, since it is larger than the sum of its proper divisors (9636234175647).
20013134214753 is a wasteful number, since it uses less digits than its factorization.
20013134214753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7016629 (or 7016623 counting only the distinct ones).
The product of its (nonzero) digits is 60480, while the sum is 36.
Adding to 20013134214753 its reverse (35741243131002), we get a palindrome (55754377345755).
The spelling of 20013134214753 in words is "twenty trillion, thirteen billion, one hundred thirty-four million, two hundred fourteen thousand, seven hundred fifty-three".
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