200143330444041 has 4 divisors (see below), whose sum is σ = 266857773925392. Its totient is φ = 133428886962692.

The previous prime is 200143330444039. The next prime is 200143330444051. The reversal of 200143330444041 is 140444033341002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200143330444041 - 2¹ = 200143330444039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200143330443993 and 200143330444011.

It is not an unprimeable number, because it can be changed into a prime (200143330444051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33357221740671 + ... + 33357221740676.

It is an arithmetic number, because the mean of its divisors is an integer number (66714443481348).

Almost surely, 2^{200143330444041} is an apocalyptic number.

It is an amenable number.

200143330444041 is a deficient number, since it is larger than the sum of its proper divisors (66714443481351).

200143330444041 is an equidigital number, since it uses as much as digits as its factorization.

200143330444041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66714443481350.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 200143330444041 its reverse (140444033341002), we get a palindrome (340587363785043).

The spelling of 200143330444041 in words is "two hundred trillion, one hundred forty-three billion, three hundred thirty million, four hundred forty-four thousand, forty-one".