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2001632115145 = 513161017191249
BaseRepresentation
bin11101001000001010100…
…100100011100111001001
321002100120011221220001011
4131020022210203213021
5230243320310141040
64131312002523521
7264420211153165
oct35101244434711
97070504856034
102001632115145
11701984168083
12283b1a6665a1
131169a3732a90
146cc45543ca5
15371014223ea
hex1d20a9239c9

2001632115145 has 16 divisors (see below), whose sum is σ = 2586754170000. Its totient is φ = 1478111422464.

The previous prime is 2001632115113. The next prime is 2001632115173. The reversal of 2001632115145 is 5415112361002.

It can be written as a sum of positive squares in 8 ways, for example, as 542008108944 + 1459624006201 = 736212^2 + 1208149^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001632115145 - 25 = 2001632115113 is a prime.

It is a super-2 number, since 2×20016321151452 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10370481 + ... + 10561729.

It is an arithmetic number, because the mean of its divisors is an integer number (161672135625).

Almost surely, 22001632115145 is an apocalyptic number.

It is an amenable number.

2001632115145 is a deficient number, since it is larger than the sum of its proper divisors (585122054855).

2001632115145 is a wasteful number, since it uses less digits than its factorization.

2001632115145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 352284.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 2001632115145 its reverse (5415112361002), we get a palindrome (7416744476147).

The spelling of 2001632115145 in words is "two trillion, one billion, six hundred thirty-two million, one hundred fifteen thousand, one hundred forty-five".

Divisors: 1 5 13 65 161017 191249 805085 956245 2093221 2486237 10466105 12431185 30794340233 153971701165 400326423029 2001632115145