Base | Representation |
---|---|
bin | 10010101001001100… |
… | …000000010000100001 |
3 | 1220200010002022221110 |
4 | 102221030000100201 |
5 | 311444200143343 |
6 | 13110223013533 |
7 | 1306034204361 |
oct | 225114002041 |
9 | 56603068843 |
10 | 20018365473 |
11 | 85429332a7 |
12 | 3a6813a2a9 |
13 | 1b70438092 |
14 | d7c9069a1 |
15 | 7c2697833 |
hex | 4a9300421 |
20018365473 has 4 divisors (see below), whose sum is σ = 26691153968. Its totient is φ = 13345576980.
The previous prime is 20018365459. The next prime is 20018365481. The reversal of 20018365473 is 37456381002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 20018365473 - 25 = 20018365441 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (20018365373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3336394243 + ... + 3336394248.
It is an arithmetic number, because the mean of its divisors is an integer number (6672788492).
Almost surely, 220018365473 is an apocalyptic number.
It is an amenable number.
20018365473 is a deficient number, since it is larger than the sum of its proper divisors (6672788495).
20018365473 is an equidigital number, since it uses as much as digits as its factorization.
20018365473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6672788494.
The product of its (nonzero) digits is 120960, while the sum is 39.
The spelling of 20018365473 in words is "twenty billion, eighteen million, three hundred sixty-five thousand, four hundred seventy-three".
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