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2002000010011 = 5571735931583
BaseRepresentation
bin11101001000100000011…
…111111101101100011011
321002101111211012212220221
4131020200133331230123
5230300044000310021
64131412304100511
7264432266211031
oct35104037755433
97071454185827
102002000010011
117020528a4a21
12284001904737
13116a31a13151
146cc7c34c551
1537123893241
hex1d2207fdb1b

2002000010011 has 4 divisors (see below), whose sum is σ = 2002035997312. Its totient is φ = 2001964022712.

The previous prime is 2002000010009. The next prime is 2002000010029. The reversal of 2002000010011 is 1100100002002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002000010011 - 21 = 2002000010009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002000009976 and 2002000010003.

It is not an unprimeable number, because it can be changed into a prime (2002000010051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17910075 + ... + 18021508.

It is an arithmetic number, because the mean of its divisors is an integer number (500508999328).

Almost surely, 22002000010011 is an apocalyptic number.

2002000010011 is a deficient number, since it is larger than the sum of its proper divisors (35987301).

2002000010011 is an equidigital number, since it uses as much as digits as its factorization.

2002000010011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35987300.

The product of its (nonzero) digits is 4, while the sum is 7.

Adding to 2002000010011 its reverse (1100100002002), we get a palindrome (3102100012013).

The spelling of 2002000010011 in words is "two trillion, two billion, ten thousand, eleven".

Divisors: 1 55717 35931583 2002000010011