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2002100403 = 3667366801
BaseRepresentation
bin111011101010101…
…1010000010110011
312011112022020102210
41313111122002303
513100014203103
6530355543203
7100420400262
oct16725320263
95145266383
102002100403
11938151736
1247a5bab03
1325ba313c4
1414dc845d9
15bab79e03
hex7755a0b3

2002100403 has 4 divisors (see below), whose sum is σ = 2669467208. Its totient is φ = 1334733600.

The previous prime is 2002100383. The next prime is 2002100417. The reversal of 2002100403 is 3040012002.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2002100403 - 217 = 2001969331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002140403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333683398 + ... + 333683403.

It is an arithmetic number, because the mean of its divisors is an integer number (667366802).

Almost surely, 22002100403 is an apocalyptic number.

2002100403 is a deficient number, since it is larger than the sum of its proper divisors (667366805).

2002100403 is an equidigital number, since it uses as much as digits as its factorization.

2002100403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 667366804.

The product of its (nonzero) digits is 48, while the sum is 12.

The square root of 2002100403 is about 44744.8366071438. The cubic root of 2002100403 is about 1260.3619525775.

Adding to 2002100403 its reverse (3040012002), we get a palindrome (5042112405).

The spelling of 2002100403 in words is "two billion, two million, one hundred thousand, four hundred three".

Divisors: 1 3 667366801 2002100403