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2002111431241 = 2238978078167
BaseRepresentation
bin11101001000100111001…
…001000000001001001001
321002101210120212200010011
4131020213021000021021
5230300311011244431
64131431324151521
7264435121242205
oct35104711001111
97071716780104
102002111431241
117020aa787389
122840330985a1
13116a4bb2537c
146cc8d073b05
153712d551cb1
hex1d227240249

2002111431241 has 4 divisors (see below), whose sum is σ = 2011089509632. Its totient is φ = 1993133352852.

The previous prime is 2002111431239. The next prime is 2002111431401. The reversal of 2002111431241 is 1421341112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002111431241 - 21 = 2002111431239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002111431211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4489038861 + ... + 4489039306.

It is an arithmetic number, because the mean of its divisors is an integer number (502772377408).

Almost surely, 22002111431241 is an apocalyptic number.

It is an amenable number.

2002111431241 is a deficient number, since it is larger than the sum of its proper divisors (8978078391).

2002111431241 is an equidigital number, since it uses as much as digits as its factorization.

2002111431241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8978078390.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 2002111431241 its reverse (1421341112002), we get a palindrome (3423452543243).

The spelling of 2002111431241 in words is "two trillion, two billion, one hundred eleven million, four hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 223 8978078167 2002111431241