Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …011100011011100011001 |
3 | 21002101210122010122122111 |
4 | 131020213023203130121 |
5 | 230300311144200441 |
6 | 4131431350352321 |
7 | 264435130026250 |
oct | 35104713433431 |
9 | 7071718118574 |
10 | 2002112100121 |
11 | 7021000a3981 |
12 | 28403335b6a1 |
13 | 116a4bcca963 |
14 | 6cc8d1a9797 |
15 | 3712d635081 |
hex | 1d2272e3719 |
2002112100121 has 8 divisors (see below), whose sum is σ = 2408555910080. Its totient is φ = 1625775239088.
The previous prime is 2002112100103. The next prime is 2002112100143. The reversal of 2002112100121 is 1210012112002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2002112100121 - 25 = 2002112100089 is a prime.
It is a super-2 number, since 2×20021121001212 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2002112104121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7526737086 + ... + 7526737351.
It is an arithmetic number, because the mean of its divisors is an integer number (301069488760).
Almost surely, 22002112100121 is an apocalyptic number.
It is an amenable number.
2002112100121 is a deficient number, since it is larger than the sum of its proper divisors (406443809959).
2002112100121 is a wasteful number, since it uses less digits than its factorization.
2002112100121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15053474463.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2002112100121 its reverse (1210012112002), we get a palindrome (3212124212123).
The spelling of 2002112100121 in words is "two trillion, two billion, one hundred twelve million, one hundred thousand, one hundred twenty-one".
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