Base | Representation |
---|---|
bin | 1011101001110110001… |
… | …0000000011100011001 |
3 | 201010210002010121101012 |
4 | 2322131202000130121 |
5 | 11240013111330431 |
6 | 231550441503305 |
7 | 20315266050311 |
oct | 2723542003431 |
9 | 633702117335 |
10 | 200211433241 |
11 | 77a00153116 |
12 | 329764a1b35 |
13 | 15b5907a4c1 |
14 | 99941dc441 |
15 | 531bcdb22b |
hex | 2e9d880719 |
200211433241 has 4 divisors (see below), whose sum is σ = 200216336400. Its totient is φ = 200206530084.
The previous prime is 200211433237. The next prime is 200211433243. The reversal of 200211433241 is 142334112002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 200211433241 - 22 = 200211433237 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200211433243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2389811 + ... + 2472168.
It is an arithmetic number, because the mean of its divisors is an integer number (50054084100).
Almost surely, 2200211433241 is an apocalyptic number.
It is an amenable number.
200211433241 is a deficient number, since it is larger than the sum of its proper divisors (4903159).
200211433241 is an equidigital number, since it uses as much as digits as its factorization.
200211433241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4903158.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 200211433241 its reverse (142334112002), we get a palindrome (342545545243).
The spelling of 200211433241 in words is "two hundred billion, two hundred eleven million, four hundred thirty-three thousand, two hundred forty-one".
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