Base | Representation |
---|---|
bin | 101101100001011101111101… |
… | …110011101101010100010011 |
3 | 222020220002012022010102122120 |
4 | 231201131331303231110103 |
5 | 202220233144332210003 |
6 | 1545452043405305323 |
7 | 60112561165004502 |
oct | 5541357563552423 |
9 | 866802168112576 |
10 | 200212011210003 |
11 | 588804898a2391 |
12 | 1a556519565243 |
13 | 8793bb0b690c0 |
14 | 3762455000839 |
15 | 1822e91c4a853 |
hex | b6177dced513 |
200212011210003 has 8 divisors (see below), whose sum is σ = 287483913532368. Its totient is φ = 123207391513824.
The previous prime is 200212011209981. The next prime is 200212011210019. The reversal of 200212011210003 is 300012110212002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 200212011210003 - 29 = 200212011209491 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200212011260003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2566820656500 + ... + 2566820656577.
It is an arithmetic number, because the mean of its divisors is an integer number (35935489191546).
Almost surely, 2200212011210003 is an apocalyptic number.
200212011210003 is a deficient number, since it is larger than the sum of its proper divisors (87271902322365).
200212011210003 is a wasteful number, since it uses less digits than its factorization.
200212011210003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5133641313093.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 200212011210003 its reverse (300012110212002), we get a palindrome (500224121422005).
The spelling of 200212011210003 in words is "two hundred trillion, two hundred twelve billion, eleven million, two hundred ten thousand, three".
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