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200212011210003 = 3135133641313077
BaseRepresentation
bin101101100001011101111101…
…110011101101010100010011
3222020220002012022010102122120
4231201131331303231110103
5202220233144332210003
61545452043405305323
760112561165004502
oct5541357563552423
9866802168112576
10200212011210003
11588804898a2391
121a556519565243
138793bb0b690c0
143762455000839
151822e91c4a853
hexb6177dced513

200212011210003 has 8 divisors (see below), whose sum is σ = 287483913532368. Its totient is φ = 123207391513824.

The previous prime is 200212011209981. The next prime is 200212011210019. The reversal of 200212011210003 is 300012110212002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 200212011210003 - 29 = 200212011209491 is a prime.

It is not an unprimeable number, because it can be changed into a prime (200212011260003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2566820656500 + ... + 2566820656577.

It is an arithmetic number, because the mean of its divisors is an integer number (35935489191546).

Almost surely, 2200212011210003 is an apocalyptic number.

200212011210003 is a deficient number, since it is larger than the sum of its proper divisors (87271902322365).

200212011210003 is a wasteful number, since it uses less digits than its factorization.

200212011210003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5133641313093.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 200212011210003 its reverse (300012110212002), we get a palindrome (500224121422005).

The spelling of 200212011210003 in words is "two hundred trillion, two hundred twelve billion, eleven million, two hundred ten thousand, three".

Divisors: 1 3 13 39 5133641313077 15400923939231 66737337070001 200212011210003