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2002121102011 = 5093933440279
BaseRepresentation
bin11101001000100111101…
…101111001001010111011
321002101211021001222220211
4131020213231321022323
5230300321000231021
64131432311331551
7264435266400652
oct35104755711273
97071737058824
102002121102011
11702105192158
12284036380bb7
13116a50b30114
146cc90470199
153712e3123e1
hex1d227b792bb

2002121102011 has 4 divisors (see below), whose sum is σ = 2006054542800. Its totient is φ = 1998187661224.

The previous prime is 2002121101973. The next prime is 2002121102057. The reversal of 2002121102011 is 1102011212002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2002121102011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002121101982 and 2002121102000.

It is not an unprimeable number, because it can be changed into a prime (2002121102081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1966719631 + ... + 1966720648.

It is an arithmetic number, because the mean of its divisors is an integer number (501513635700).

Almost surely, 22002121102011 is an apocalyptic number.

2002121102011 is a deficient number, since it is larger than the sum of its proper divisors (3933440789).

2002121102011 is an equidigital number, since it uses as much as digits as its factorization.

2002121102011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3933440788.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2002121102011 its reverse (1102011212002), we get a palindrome (3104132314013).

The spelling of 2002121102011 in words is "two trillion, two billion, one hundred twenty-one million, one hundred two thousand, eleven".

Divisors: 1 509 3933440279 2002121102011