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200212113131 = 367545537093
BaseRepresentation
bin1011101001110110010…
…0100110011011101011
3201010210010102011000022
42322131210212123223
511240013300110011
6231550504231055
720315304611432
oct2723544463353
9633703364008
10200212113131
1177a00577a08
123297676b48b
1315b59257ac4
149994338119
15531bdc28db
hex2e9d9266eb

200212113131 has 4 divisors (see below), whose sum is σ = 200757650592. Its totient is φ = 199666575672.

The previous prime is 200212113119. The next prime is 200212113133. The reversal of 200212113131 is 131311212002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200212113131 - 230 = 199138371307 is a prime.

It is a super-2 number, since 2×2002121131312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200212113133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272768180 + ... + 272768913.

It is an arithmetic number, because the mean of its divisors is an integer number (50189412648).

Almost surely, 2200212113131 is an apocalyptic number.

200212113131 is a deficient number, since it is larger than the sum of its proper divisors (545537461).

200212113131 is an equidigital number, since it uses as much as digits as its factorization.

200212113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 545537460.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 200212113131 its reverse (131311212002), we get a palindrome (331523325133).

The spelling of 200212113131 in words is "two hundred billion, two hundred twelve million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 367 545537093 200212113131