Base | Representation |
---|---|
bin | 101101100001011110010111… |
… | …101000010010011101001011 |
3 | 222020220010022111021222112211 |
4 | 231201132113220102131023 |
5 | 202220240041233032021 |
6 | 1545452154402445551 |
7 | 60112605005162215 |
oct | 5541362750223513 |
9 | 866803274258484 |
10 | 200212444424011 |
11 | 58880691393498 |
12 | 1a55661a6638b7 |
13 | 8793c4c839556 |
14 | 376249676d5b5 |
15 | 1822eb9cc03e1 |
hex | b61797a1274b |
200212444424011 has 4 divisors (see below), whose sum is σ = 200844029422512. Its totient is φ = 199580859425512.
The previous prime is 200212444423969. The next prime is 200212444424021. The reversal of 200212444424011 is 110424444212002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200212444424011 - 211 = 200212444421963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200212444424021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315792498775 + ... + 315792499408.
It is an arithmetic number, because the mean of its divisors is an integer number (50211007355628).
Almost surely, 2200212444424011 is an apocalyptic number.
200212444424011 is a deficient number, since it is larger than the sum of its proper divisors (631584998501).
200212444424011 is an equidigital number, since it uses as much as digits as its factorization.
200212444424011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 631584998500.
The product of its (nonzero) digits is 16384, while the sum is 31.
Adding to 200212444424011 its reverse (110424444212002), we get a palindrome (310636888636013).
The spelling of 200212444424011 in words is "two hundred trillion, two hundred twelve billion, four hundred forty-four million, four hundred twenty-four thousand, eleven".
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