2002130113 has 4 divisors (see below), whose sum is σ = 2032012720. Its totient is φ = 1972247508.

The previous prime is 2002130107. The next prime is 2002130129. The reversal of 2002130113 is 3110312002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002130113 - 2⁹ = 2002129601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002130093 and 2002130102.

It is not an unprimeable number, because it can be changed into a prime (2002130213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14941203 + ... + 14941336.

It is an arithmetic number, because the mean of its divisors is an integer number (508003180).

Almost surely, 2^2002130113 is an apocalyptic number.

It is an amenable number.

2002130113 is a deficient number, since it is larger than the sum of its proper divisors (29882607).

2002130113 is an equidigital number, since it uses as much as digits as its factorization.

2002130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29882606.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 2002130113 is about 44745.1685995259. The cubic root of 2002130113 is about 1260.3681868916.

Adding to 2002130113 its reverse (3110312002), we get a palindrome (5112442115).

The spelling of 2002130113 in words is "two billion, two million, one hundred thirty thousand, one hundred thirteen".