2002131313001 has 4 divisors (see below), whose sum is σ = 2002134192852. Its totient is φ = 2002128433152.

The previous prime is 2002131312943. The next prime is 2002131313003. The reversal of 2002131313001 is 1003131312002.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 88402155625 + 1913729157376 = 297325^2 + 1383376^2 .

It is a cyclic number.

It is not a de Polignac number, because 2002131313001 - 2¹⁰ = 2002131311977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002131313003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 319565 + ... + 2026421.

It is an arithmetic number, because the mean of its divisors is an integer number (500533548213).

Almost surely, 2^{2002131313001} is an apocalyptic number.

It is an amenable number.

2002131313001 is a deficient number, since it is larger than the sum of its proper divisors (2879851).

2002131313001 is a wasteful number, since it uses less digits than its factorization.

2002131313001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2879850.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 2002131313001 its reverse (1003131312002), we get a palindrome (3005262625003).

Subtracting from 2002131313001 its reverse (1003131312002), we obtain a palindrome (999000000999).

It can be divided in two parts, 2002131 and 313001, that added together give a palindrome (2315132).

The spelling of 2002131313001 in words is "two trillion, two billion, one hundred thirty-one million, three hundred thirteen thousand, one".