Base | Representation |
---|---|
bin | 101101100001011111000000… |
… | …101110110100000100010001 |
3 | 222020220012002112212002112010 |
4 | 231201133000232310010101 |
5 | 202220242444301003101 |
6 | 1545452351034453133 |
7 | 60112631050401054 |
oct | 5541370056640421 |
9 | 866805075762463 |
10 | 200213134000401 |
11 | 58880a05663435 |
12 | 1a5567915941a9 |
13 | 879402c669312 |
14 | 3762520192a9b |
15 | 182300a5d42d6 |
hex | b617c0bb4111 |
200213134000401 has 8 divisors (see below), whose sum is σ = 267235744852384. Its totient is φ = 133332972907680.
The previous prime is 200213134000357. The next prime is 200213134000427. The reversal of 200213134000401 is 104000431312002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 200213134000401 - 218 = 200213133738257 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200213133000401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35612436535 + ... + 35612442156.
It is an arithmetic number, because the mean of its divisors is an integer number (33404468106548).
Almost surely, 2200213134000401 is an apocalyptic number.
It is an amenable number.
200213134000401 is a deficient number, since it is larger than the sum of its proper divisors (67022610851983).
200213134000401 is an equidigital number, since it uses as much as digits as its factorization.
200213134000401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71224879631.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 200213134000401 its reverse (104000431312002), we get a palindrome (304213565312403).
The spelling of 200213134000401 in words is "two hundred trillion, two hundred thirteen billion, one hundred thirty-four million, four hundred one", and thus it is an aban number.
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