20021321310001 has 4 divisors (see below), whose sum is σ = 21841441429104. Its totient is φ = 18201201190900.

The previous prime is 20021321309993. The next prime is 20021321310013. The reversal of 20021321310001 is 10001312312002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20021321310001 - 2³ = 20021321309993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20021321311001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 910060059535 + ... + 910060059556.

It is an arithmetic number, because the mean of its divisors is an integer number (5460360357276).

Almost surely, 2^{20021321310001} is an apocalyptic number.

It is an amenable number.

20021321310001 is a deficient number, since it is larger than the sum of its proper divisors (1820120119103).

20021321310001 is a wasteful number, since it uses less digits than its factorization.

20021321310001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1820120119102.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 20021321310001 its reverse (10001312312002), we get a palindrome (30022633622003).

It can be divided in two parts, 2002132 and 1310001, that added together give a palindrome (3312133).

The spelling of 20021321310001 in words is "twenty trillion, twenty-one billion, three hundred twenty-one million, three hundred ten thousand, one".