Search a number
-
+
200213331121 = 859233077219
BaseRepresentation
bin1011101001110110100…
…1001111110010110001
3201010210012201000210001
42322131221033302301
511240014103043441
6231550550310001
720315321143426
oct2723551176261
9633705630701
10200213331121
1177a0122a011
1232977058301
1315b595932cb
149994573d4d
15531c063731
hex2e9da4fcb1

200213331121 has 4 divisors (see below), whose sum is σ = 200446409200. Its totient is φ = 199980253044.

The previous prime is 200213331067. The next prime is 200213331163. The reversal of 200213331121 is 121133312002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200213331121 - 29 = 200213330609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200213331191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116537751 + ... + 116539468.

It is an arithmetic number, because the mean of its divisors is an integer number (50111602300).

Almost surely, 2200213331121 is an apocalyptic number.

It is an amenable number.

200213331121 is a deficient number, since it is larger than the sum of its proper divisors (233078079).

200213331121 is an equidigital number, since it uses as much as digits as its factorization.

200213331121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233078078.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 200213331121 its reverse (121133312002), we get a palindrome (321346643123).

The spelling of 200213331121 in words is "two hundred billion, two hundred thirteen million, three hundred thirty-one thousand, one hundred twenty-one".

Divisors: 1 859 233077219 200213331121