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2002213330403 = 111314001491821
BaseRepresentation
bin11101001000101101001…
…101101101110111100011
321002102001200121200111012
4131020231031231313203
5230301013103033103
64131445404211135
7264440466334256
oct35105515556743
97072050550435
102002213330403
11702152255770
12284061239aab
13116a66c82430
146cc9c7db09d
153713747e2d8
hex1d22d36dde3

2002213330403 has 8 divisors (see below), whose sum is σ = 2352250626096. Its totient is φ = 1680179018400.

The previous prime is 2002213330399. The next prime is 2002213330451. The reversal of 2002213330403 is 3040333122002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2002213330403 - 22 = 2002213330399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002213330003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7000745768 + ... + 7000746053.

It is an arithmetic number, because the mean of its divisors is an integer number (294031328262).

Almost surely, 22002213330403 is an apocalyptic number.

2002213330403 is a deficient number, since it is larger than the sum of its proper divisors (350037295693).

2002213330403 is a wasteful number, since it uses less digits than its factorization.

2002213330403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14001491845.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 2002213330403 its reverse (3040333122002), we get a palindrome (5042546452405).

The spelling of 2002213330403 in words is "two trillion, two billion, two hundred thirteen million, three hundred thirty thousand, four hundred three".

Divisors: 1 11 13 143 14001491821 154016410031 182019393673 2002213330403