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2002320233131 = 43179411259547
BaseRepresentation
bin11101001000110011100…
…101100001001010101011
321002102100010202220110111
4131020303211201022223
5230301222434430011
64131504143355151
7264443235106111
oct35106345411253
97072303686414
102002320233131
117021a7631329
12284090bb2ab7
13116a83171a9a
146ccacaa7ab1
1537141a49121
hex1d2339612ab

2002320233131 has 8 divisors (see below), whose sum is σ = 2048905134144. Its totient is φ = 1955736210120.

The previous prime is 2002320233129. The next prime is 2002320233161. The reversal of 2002320233131 is 1313320232002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2002320233131 - 21 = 2002320233129 is a prime.

It is a super-2 number, since 2×20023202331312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2002320233161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7584900 + ... + 7844446.

It is an arithmetic number, because the mean of its divisors is an integer number (256113141768).

Almost surely, 22002320233131 is an apocalyptic number.

2002320233131 is a deficient number, since it is larger than the sum of its proper divisors (46584901013).

2002320233131 is a wasteful number, since it uses less digits than its factorization.

2002320233131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 439001.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 2002320233131 its reverse (1313320232002), we get a palindrome (3315640465133).

The spelling of 2002320233131 in words is "two trillion, two billion, three hundred twenty million, two hundred thirty-three thousand, one hundred thirty-one".

Divisors: 1 43 179411 259547 7714673 11160521 46565586817 2002320233131