20023300113 has 4 divisors (see below), whose sum is σ = 26697733488. Its totient is φ = 13348866740.

The previous prime is 20023300097. The next prime is 20023300133. The reversal of 20023300113 is 31100332002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20023300113 - 2⁴ = 20023300097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20023300092 and 20023300101.

It is not an unprimeable number, because it can be changed into a prime (20023300133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3337216683 + ... + 3337216688.

It is an arithmetic number, because the mean of its divisors is an integer number (6674433372).

Almost surely, 2^20023300113 is an apocalyptic number.

It is an amenable number.

20023300113 is a deficient number, since it is larger than the sum of its proper divisors (6674433375).

20023300113 is an equidigital number, since it uses as much as digits as its factorization.

20023300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6674433374.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 20023300113 its reverse (31100332002), we get a palindrome (51123632115).

The spelling of 20023300113 in words is "twenty billion, twenty-three million, three hundred thousand, one hundred thirteen".