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20023466432001 = 36674488810667
BaseRepresentation
bin1001000110110000100111…
…00110101001011000000001
32121220020001210200202122220
410203120103212221120001
510111031024401311001
6110330353053121253
74134435110266344
oct443302346513001
977806053622586
1020023466432001
11641a9a487679a
1222b4822489229
13b23287ba3c66
144d31d8a8445b
1524acca0ccc36
hex1236139a9601

20023466432001 has 4 divisors (see below), whose sum is σ = 26697955242672. Its totient is φ = 13348977621332.

The previous prime is 20023466431921. The next prime is 20023466432017. The reversal of 20023466432001 is 10023466432002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20023466432001 - 29 = 20023466431489 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20023466432041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3337244405331 + ... + 3337244405336.

It is an arithmetic number, because the mean of its divisors is an integer number (6674488810668).

Almost surely, 220023466432001 is an apocalyptic number.

It is an amenable number.

20023466432001 is a deficient number, since it is larger than the sum of its proper divisors (6674488810671).

20023466432001 is an equidigital number, since it uses as much as digits as its factorization.

20023466432001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6674488810670.

The product of its (nonzero) digits is 41472, while the sum is 33.

Subtracting from 20023466432001 its reverse (10023466432002), we obtain a palindrome (9999999999999).

The spelling of 20023466432001 in words is "twenty trillion, twenty-three billion, four hundred sixty-six million, four hundred thirty-two thousand, one".

Divisors: 1 3 6674488810667 20023466432001