200240201231131 has 4 divisors (see below), whose sum is σ = 200445155378712. Its totient is φ = 200035247083552.

The previous prime is 200240201231117. The next prime is 200240201231153. The reversal of 200240201231131 is 131132102042002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200240201231131 - 2¹³ = 200240201222939 is a prime.

It is a super-2 number, since 2×200240201231131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200240201231111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102477072325 + ... + 102477074278.

It is an arithmetic number, because the mean of its divisors is an integer number (50111288844678).

Almost surely, 2^{200240201231131} is an apocalyptic number.

200240201231131 is a deficient number, since it is larger than the sum of its proper divisors (204954147581).

200240201231131 is an equidigital number, since it uses as much as digits as its factorization.

200240201231131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 204954147580.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 200240201231131 its reverse (131132102042002), we get a palindrome (331372303273133).

The spelling of 200240201231131 in words is "two hundred trillion, two hundred forty billion, two hundred one million, two hundred thirty-one thousand, one hundred thirty-one".