Base | Representation |
---|---|
bin | 1001000110110011011111… |
… | …10010110110010110110011 |
3 | 2121220101001121002101222200 |
4 | 10203121233302312112303 |
5 | 10111042211330303041 |
6 | 110331210344234243 |
7 | 4134521331120021 |
oct | 443315762662663 |
9 | 77811047071880 |
10 | 20025013134771 |
11 | 6420618955447 |
12 | 22b4b9446b983 |
13 | b234734688b8 |
14 | 4d3304263711 |
15 | 24ad6aca01b6 |
hex | 12366fcb65b3 |
20025013134771 has 12 divisors (see below), whose sum is σ = 28926397874400. Its totient is φ = 13349372340240.
The previous prime is 20025013134739. The next prime is 20025013134781. The reversal of 20025013134771 is 17743131052002.
20025013134771 is a `hidden beast` number, since 2 + 0 + 0 + 2 + 50 + 131 + 3 + 477 + 1 = 666.
It is not a de Polignac number, because 20025013134771 - 25 = 20025013134739 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20025013134781) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 52835371 + ... + 53213028.
It is an arithmetic number, because the mean of its divisors is an integer number (2410533156200).
Almost surely, 220025013134771 is an apocalyptic number.
20025013134771 is a deficient number, since it is larger than the sum of its proper divisors (8901384739629).
20025013134771 is a wasteful number, since it uses less digits than its factorization.
20025013134771 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106069386 (or 106069383 counting only the distinct ones).
The product of its (nonzero) digits is 35280, while the sum is 36.
Adding to 20025013134771 its reverse (17743131052002), we get a palindrome (37768144186773).
The spelling of 20025013134771 in words is "twenty trillion, twenty-five billion, thirteen million, one hundred thirty-four thousand, seven hundred seventy-one".
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